Which of the following transition leads to the emission of high energy photons?

Answer & explanation
Correct answer: option 4
During emission, the electron make a transition from higher excited state to lower excited state. The energy of nth excited state is given by
En = -13.6/n2
So, E2-E1 = 10.2 eV
E3-E1 = 12.09 eV
This clearly shows that the transition D will release high energy photon.