Target Exam

CUET

Subject

Physics

Chapter

Moving Charges and Magnetism

Question:

A straight horizontal wire of mass 10 mg and length 1 m carries a current of 2 ampere .What minimum magnetic field B should be applied in the region so that the magnetic force on the wire may balance its weight.

Options:

$2.45 × 10^{-4} T$

$4.9 x 10^{-4} T$

$4.9 x 10^{-5} T$

$9.8 × 10^{-4} T$

Correct Answer:

$4.9 x 10^{-5} T$

Explanation:

$\text{For weight to be balanced by magnetic force mg = ilB}$

$\Rightarrow B = \frac{mg}{iL}= 4.9 \times 10^{-5} T$