A and B can do a piece of work in 36 days. B and C can do the same work in 60 days. A and C can do the same work in 45 days. In how many days can B alone complete the same work?
Answer & explanation
Correct answer: option 3
A + B = 36 days,
B + C = 60 days,
A + C = 45 days,
⇒ Adding all the efficiency, we get,
2(A + B + C) = 12,
⇒ A + B + C = 6,
Putting value of A + C, we get B,
⇒ B + 4 = 6
⇒ B = 2
Hence, time required by B to complete the work alone = \(\frac{180}{2}\) = 90 days. ..(\(\frac{Work}{Efficiency}\) = Time )