If one of the charge is made double its value and is now placed inside water (relative permittivity : 80), how will the force change if initially the force was F?
Answer & explanation
Correct answer: option 3
F' = 2F/80 = F/40
If one of the charge is made double its value and is now placed inside water (relative permittivity : 80), how will the force change if initially the force was F?
Correct answer: option 3
F' = 2F/80 = F/40