CUET Preparation Today
CUET
-- Mathematics - Section A
Probability
If $4P(A)= 6, P(B) = 10, P(A ∩ B)= 1,$ then $P\left(\frac{B}{A}\right)=$
$\frac{2}{5}$
$\frac{3}{5}$
$\frac{7}{10}$
$\frac{19}{60}$
$P\left(\frac{B}{A}\right) = \frac{P(A∩B)}{P(A)}=\frac{(1/10)}{(1/4)}=\frac{2}{5}.$