A ball possesses 3000 units momentum. What would be the ball's new momentum if its velocity was doubles ?

6000 units

The correct answer is option 2. 6000 units.

The momentum of an object is given by the product of its mass and velocity. Since the mass of the ball is not given, we can assume it remains constant, so we can use the formula:

\[ \text{Momentum} = \text{Mass} \times \text{Velocity} \]

Given that the momentum of the ball initially is 3000 units, let's denote the initial velocity as \( v_1 \).

\[ \text{Momentum}_1 = \text{Mass} \times v_1 \]

If the velocity is doubled, the new velocity is \( 2v_1 \). Thus, the new momentum (\( \text{Momentum}_2 \)) can be expressed as:

\[ \text{Momentum}_2 = \text{Mass} \times (2v_1) = 2 \times (\text{Mass} \times v_1) = 2 \times \text{Momentum}_1 \]

Given that the initial momentum (\( \text{Momentum}_1 \)) is 3000 units, doubling it will give:

\[ \text{Momentum}_2 = 2 \times 3000 = 6000 \text{ units} \]

So, the ball's new momentum would be 6000 units.