If \(\int f(x)dx=F(x)+c\), then \(\int f(ax+b)dx=\)1\(F(ax+b)+c\)2\(aF(ax+b)+c\)3\(\frac{F(ax+b)}{a}+c\)4\(F(x)+c\)Answer & explanation+Correct answer: option 3Put \(ax+b=t\)
