If \(\int f(x)dx=F(x)+c\), then \(\int f(ax+b)dx=\)

\(F(ax+b)+c\) \(aF(ax+b)+c\) \(\frac{F(ax+b)}{a}+c\) \(F(x)+c\)

\(\frac{F(ax+b)}{a}+c\)

Put \(ax+b=t\)