A truck covers a distance of 480 km at a certain speed. If the speed is decreased by 8 km/h, it would have taken 2 hours more to cover the same distance. 50% of its original speed (in km/h) is:

24

Let initial speed = S km/h

So , New Speed = ( S - 8) km/h

We know ,

Time =  $\frac{Distance}{Speed}$

According to question ,

 $\frac{480}{S - 8 }$ -  $\frac{480}{S}$ = 2 hours

 $\frac{240× 8  }{S ( S - 8)}$ = 1

1920 = S(S-8)

S =  48 km/h

50% of S = $\frac{1}{2}$ × 48 = 24 km/h

So , 50% of initial speed is 24 km/h