A truck covers a distance of 480 km at a certain speed. If the speed is decreased by 8 km/h, it would have taken 2 hours more to cover the same distance. 50% of its original speed (in km/h) is:

24

Let initial speed = S km/h

So , New Speed = ( S - 8) km/h

We know ,

Time =  \(\frac{Distance}{Speed}\)

According to question ,

 \(\frac{480}{S - 8 }\) -  \(\frac{480}{S}\) = 2 hours

 \(\frac{240× 8  }{S ( S - 8)}\) = 1

1920 = S(S-8)

S =  48 km/h

50% of S = \(\frac{1}{2}\) × 48 = 24 km/h

So , 50% of initial speed is 24 km/h