A truck covers a distance of 480 km at a certain speed. If the speed is decreased by 8 km/h, it would have taken 2 hours more to cover the same distance. 50% of its original speed (in km/h) is: |
20 40 48 24 |
24 |
Let initial speed = S km/h So , New Speed = ( S - 8) km/h We know , Time = \(\frac{Distance}{Speed}\) According to question , \(\frac{480}{S - 8 }\) - \(\frac{480}{S}\) = 2 hours \(\frac{240× 8 }{S ( S - 8)}\) = 1 1920 = S(S-8) S = 48 km/h 50% of S = \(\frac{1}{2}\) × 48 = 24 km/h So , 50% of initial speed is 24 km/h |