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-- Mathematics - Section B1
Continuity and Differentiability
The value of c for which the conclusion of mean value theorem-holds for the function f(x)=logex on the interval [1,3], is
2log3e
12loge3
log3e
loge3
Using Mean Value Theorem, we have
f′(c)=f(3)−f(1)3−1⇒1c=12{log3−log1}⇒c=2log3e