A 1800 metres long train crosses a man walking in opposite direction in 10 seconds. If the speed of train is 8 times to the speed of man, then what is the speed of train?
Answer & explanation
Correct answer: option 1
Given :-
speed of train is 8 times to the speed of man
Let speed of man = x m/sec
Speed of train = 8x m/sec
Relative speed ( When both moves in opposite direction ) = x + 8x = 9x m/sec
Speed = \(\frac{Distance}{Time}\)
= \(\frac{1800}{10}\) = 180 m/sec
According to question ,
9x = 180
x = 20 m/sec
So , speed of train = 8x = 8 × 20 = 160 m/sec
160 m/sec = 160 × \(\frac{18}{5}\) km/h = 576 km/h