Let $A = [a_{ij}]$ be a square matrix of order n such that $a_{ij}=\left\{\begin{matrix}0,&if\,i≠j\\i,&if\,i=j\end{matrix}\right.$

Statement-1: The inverse of A is the matrix $B = [b_{ij}]$ such that $b_{ij}=\left\{\begin{matrix}0,&if\,i≠j\\\frac{1}{i},&if\,i=j\end{matrix}\right.$

Statement-2: The inverse of a diagonal matrix is a scalar matrix.

Statement-1 is True, Statement-2 is False. 

We know that the inverse of a diagonal matrix

$D= diag (d_1, d_2, d_3...,d_n)$ is a diagonal matrix given by

$D^{-1}=diag ({d_1}^{-1}, {d_2}^{-1}, {d_3}^{-1},..., {d_n}^{-1})$

$∴B = [b_{ij}]$ is given by

$b_{ij}=\left\{\begin{matrix}0,&if\,i≠j\\\frac{1}{i},&if\,i=j\end{matrix}\right.$

Hence, statement-1 is true and statement-2 is false.