CUET Preparation Today
A bulb is rated 40W for a 220 V supply. The peak voltage of the supply is |
$110\sqrt{2} V$ 220 V $220\sqrt{2} V$ 440 V |
$220\sqrt{2} V$ |
The correct answer is Option (3) → $220\sqrt{2} V$ The Peak voltage ($V_{peak}$) is, $V_{peak}=\sqrt{2}×V_{rms}$ $=220×\sqrt{2}=220\sqrt{2} V$ |
