The heights of two right circular cylinders are the same. Their volumes are respectively 16π m³ and 81π m³. The ratio of their base radii is

4 : 9

volume of cylinder: πr²h

Ratio - \(\frac{πr^2h }{πR^2H}\) = \(\frac{16π }{81π }\)

\(\frac{πr^2 }{πR^2}\) = \(\frac{16π }{81π }\)

\(\frac{r^2 }{R^2}\) = \(\frac{16 }{81 }\)

\(\frac{r}{R}\) = \(\frac{4 }{9 }\)