CUET Preparation Today
Find $\frac{dy}{dx}$, if $x = at^2, y = 2at$. |
$t$ $\frac{1}{t}$ $2t$ $\frac{1}{2t}$ |
$\frac{1}{t}$ |
The correct answer is Option (2) → $\frac{1}{t}$ ## Given that $x = at^2, y = 2at$ So $\frac{dx}{dt} = 2at \quad \text{and} \quad \frac{dy}{dt} = 2a$ Therefore $\frac{dy}{dx} = \frac{\frac{dy}{dt}}{\frac{dx}{dt}} = \frac{2a}{2at} = \frac{1}{t}$ |
