If $f(x)=\frac{x^3}{6}-2x^2,$ then $f''(

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Target Exam

CUET

Subject

-- Applied Mathematics - Section B2

Chapter

Calculus

Question:

If $f(x)=\frac{x^3}{6}-2x^2,$ then $f''(4) = ?$

Options:

-8

-4

Correct Answer:

Explanation:

The correct answer is Option (4) → 0

$f(x)=\frac{x^3}{6}-2x^2$

$f'(x)=\frac{3x^2}{6}-4x=\frac{x^2}{2}-4x$

$f''(x)=\frac{2x}{2}-4=x-4$

$∴f''(4)=4-4=0$