What is $\int_{0}^{\pi/2}\frac{\cos x}{1+\sin^2 x}dx$?1$\pi/4$2$\pi/2$3$\pi/6$40Answer & explanation+Correct answer: option 1Put $\sin x=t$, then $\cos xdx=dt$. Hence the integral becomes $\int_{0}^1\frac{1}{1+t^2}dt=\tan^{-1}t|0^{1}=\pi/4$
