Practicing Success
Practicing Success
CUET Preparation Today
| What is $\int_{0}^{\pi/2}\frac{\cos x}{1+\sin^2 x}dx$? |
$\pi/4$ $\pi/2$ $\pi/6$ 0 |
| $\pi/4$ |
| Put $\sin x=t$, then $\cos xdx=dt$. Hence the integral becomes $\int_{0}^1\frac{1}{1+t^2}dt=\tan^{-1}t|0^{1}=\pi/4$ |
