The phase angle between the voltage and the current in an LR series circuit having the same resistance as its reactance is

45°

The correct answer is Option (4) → 45°

Given:

LR series circuit with $R = X_L$

Phase angle: $\tan \phi = \frac{X_L}{R}$

Substitute $X_L = R$: $\tan \phi = \frac{R}{R} = 1 \Rightarrow \phi = 45^\circ$

Answer: $45^\circ$