Match the LIST-I with LIST-II.LIST-I(Name of reaction)LIST-II(Product…

Match the LIST-I with LIST-II.

Choose the correct answer from the options given below:

Answer & explanation

Correct answer: option 1

The correct answer is Option (1) → A-III, B-IV, C-II, D-I

These named reactions of halogen compounds form two families:

Halogen exchange: Finkelstein (R–Cl or R–Br with NaI in dry acetone gives R–I) and Swarts (R–Cl or R–Br with a metallic fluoride such as AgF gives R–F).
Coupling with sodium in dry ether: Wurtz (two alkyl halides give an alkane), Fittig (two aryl halides give diphenyl) and Wurtz–Fittig (an alkyl and an aryl halide give an alkylbenzene):
\( \displaystyle \ce{C6H5Cl + CH3Cl + 2Na} \xrightarrow{\text{dry ether}} \ce{C6H5-CH3 + 2NaCl} \)

A. Finkelstein reaction — This matches III. Alkyl Iodide. An alkyl chloride or bromide is heated with NaI in dry acetone. NaCl or NaBr is insoluble in acetone and precipitates, which drives the exchange forward.
\( \displaystyle \ce{R-X + NaI} \xrightarrow{\text{dry acetone}} \ce{R-I + NaX v}\quad(\text{X = Cl, Br}) \)
B. Fittig reaction — This matches IV. Diphenyl. Two molecules of an aryl halide are coupled by sodium in dry ether.
\( \displaystyle \ce{2C6H5Cl + 2Na} \xrightarrow{\text{dry ether}} \ce{C6H5-C6H5 + 2NaCl} \)
C. Swarts reaction — This matches II. Alkyl fluoride. An alkyl chloride or bromide is heated with a metallic fluoride such as AgF, \( \ce{Hg2F2} \), \( \ce{CoF2} \) or \( \ce{SbF3} \).
\( \displaystyle \ce{CH3Br + AgF} \xrightarrow{\text{heat}} \ce{CH3F + AgBr} \)
D. Wurtz reaction — This matches I. Alkane. Two molecules of an alkyl halide are coupled by sodium in dry ether, giving an alkane with double the number of carbons.
\( \displaystyle \ce{2CH3Br + 2Na} \xrightarrow{\text{dry ether}} \ce{CH3-CH3 + 2NaBr} \)

Shortcut: The pair C–II appears only in Options (1) and (2), and A–III then leaves only Option (1).

Match the LIST-I with LIST-II.

Choose the correct answer from the options given below:

Answer & explanation

Correct answer: option 1

The correct answer is Option (1) → A-III, B-IV, C-II, D-I

These named reactions of halogen compounds form two families:

Halogen exchange: Finkelstein (R–Cl or R–Br with NaI in dry acetone gives R–I) and Swarts (R–Cl or R–Br with a metallic fluoride such as AgF gives R–F).
Coupling with sodium in dry ether: Wurtz (two alkyl halides give an alkane), Fittig (two aryl halides give diphenyl) and Wurtz–Fittig (an alkyl and an aryl halide give an alkylbenzene):
\( \displaystyle \ce{C6H5Cl + CH3Cl + 2Na} \xrightarrow{\text{dry ether}} \ce{C6H5-CH3 + 2NaCl} \)

A. Finkelstein reaction — This matches III. Alkyl Iodide. An alkyl chloride or bromide is heated with NaI in dry acetone. NaCl or NaBr is insoluble in acetone and precipitates, which drives the exchange forward.
\( \displaystyle \ce{R-X + NaI} \xrightarrow{\text{dry acetone}} \ce{R-I + NaX v}\quad(\text{X = Cl, Br}) \)
B. Fittig reaction — This matches IV. Diphenyl. Two molecules of an aryl halide are coupled by sodium in dry ether.
\( \displaystyle \ce{2C6H5Cl + 2Na} \xrightarrow{\text{dry ether}} \ce{C6H5-C6H5 + 2NaCl} \)
C. Swarts reaction — This matches II. Alkyl fluoride. An alkyl chloride or bromide is heated with a metallic fluoride such as AgF, \( \ce{Hg2F2} \), \( \ce{CoF2} \) or \( \ce{SbF3} \).
\( \displaystyle \ce{CH3Br + AgF} \xrightarrow{\text{heat}} \ce{CH3F + AgBr} \)
D. Wurtz reaction — This matches I. Alkane. Two molecules of an alkyl halide are coupled by sodium in dry ether, giving an alkane with double the number of carbons.
\( \displaystyle \ce{2CH3Br + 2Na} \xrightarrow{\text{dry ether}} \ce{CH3-CH3 + 2NaBr} \)

Shortcut: The pair C–II appears only in Options (1) and (2), and A–III then leaves only Option (1).