A fisherman is rowing a boat. He takes 6 hours to row 48 km upstream whereas he takes 3 hours to go to the same distance downstream. (A) His speed of rowing in still water is 10 km/hour. Choose the correct answer from the options given below: |
(A) and (D) only (C) and (D) only (A), (B) and (C) only (A) and (C) only |
(C) and (D) only |
The correct answer is Option (2) → (C) and (D) only Given: Upstream distance = 48 km, time = 6 hours → upstream speed $v_u = 48/6 = 8$ km/hr Downstream distance = 48 km, time = 3 hours → downstream speed $v_d = 48/3 = 16$ km/hr Let $v$ = speed in still water, $s$ = speed of stream Upstream: $v - s = 8$, Downstream: $v + s = 16$ Solving: $v - s = 8$ $v + s = 16$ Adding: $2v = 24 \Rightarrow v = 12$ km/hr Subtracting: $2s = 8 \Rightarrow s = 4$ km/hr Average speed for the round trip = $2 \cdot 48 / (6+3) = 96/9 = 32/3$ km/hr Check statements: (A) $v = 12$ km/hr → False (statement says 10) (B) $s = 4$ km/hr → False (statement says 3) (C) Average speed = 32/3 km/hr → True (D) Speed of stream = 4 km/hr → True |