The feasible region for the set of constraints 2x - 3y ≥ 24, x ≥ 0, y ≥ 0 is:
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → Unbounded in I quadrant.
$2x - 3y \ge 24,\quad x \ge 0,\ y \ge 0$
$y \le \frac{2x - 24}{3}$
$\text{Region lies in first quadrant and extends infinitely}$
$\text{Unbounded in I quadrant}$