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The feasible region for the set of constraints 2x - 3y ≥ 24, x ≥ 0, y ≥ 0 is: |
Bounded in I quadrant. Bounded in I and IV quadrants. Unbounded in I quadrant. Unbounded in II quadrant. |
Unbounded in I quadrant. |
The correct answer is Option (3) → Unbounded in I quadrant. $2x - 3y \ge 24,\quad x \ge 0,\ y \ge 0$ $y \le \frac{2x - 24}{3}$ $\text{Region lies in first quadrant and extends infinitely}$ $\text{Unbounded in I quadrant}$ |
