The radii of two circular faces of a frustum of a cone are 8 cm and 6 cm. If the height of the frustum is 21 cm, find its volume.

3,344 cm² 3,256 cm² 2,596 cm² 2,864 cm²

3,256 cm²

Volume of frustum = \(\frac{d}{d}\) \(\pi \) (r12 + r22 + r1r2) × h = \(\frac{1}{3}\) \(\pi \) (82 + 62 + 8 × 6) × 21 = \(\frac{1}{3}\) \(\pi \) (64 + 36 + 48) × 21 = \(\frac{1}{3}\) × \(\frac{22}{7}\) × 148 × 21 = 3,256 cm3