CUET Preparation Today
D is a point on the side BC of a $\triangle$ABC such that $\angle ADC = \angle BAC$. If CA = 10 cm and BC = 16 cm then the length of CD is: |
6 cm 6.5 cm 6.25 cm 7 cm |
6.25 cm |
\(\Delta \)DCA is similar to \(\Delta \)ACB \(\frac{CD}{AC}\) = \(\frac{AC}{BC}\) = \(\frac{CD}{AC}\) = \(\frac{10}{16}\) = CD = \(\frac{10 \;×\; 10}{16}\) = 6.25 cm. |
