A train takes 6 sec and 5 sec to cross two men who are walking in opposite direction at the speed of 5 m/sec and 10 m/sec respectively. Find length of the train.
Answer & explanation
Correct answer: option 1
Train passes first person in 6 sec.
Let the length of Train is L and speed is S
\(\frac{L}{S+5}\) = 6
L = 6(S + 5) ..... (i)
Train passes the other person in 5 sec.
\(\frac{L}{S+10}\) = 5
L = 5(S + 10) ..... (ii)
From equation (i) and (ii)
6(S + 5) = 5(S + 10)
⇒ 6S + 30 = 5S + 50
S = 20 m/sec
Put the value of S in equation (i)
L = 6(20 + 5) = 150 m