In the figure, L is the centre of the circle, and ML is the perpendicular to LN. If the area of the triangle MLN is 36, then the area of the circle is: |
70π 72π 66π 68π |
72π |
We know that, Area of the circle = πr2 Area of the right-angled triangle = (1/2) × Base × Height In ΔLMN LM = LN = radius Area of right-angled ΔLMN = \(\frac{1}{2}\) × r × r = 36 = \(\frac{r^2}{2}\) = r2 = 72 Area of the circle = πr2 = 72π |