Match List-I with List-II
Choose the correct answer from the options given below : | ||||||||||||||||||||
(A)-(I), (B)-(III),(C)-(II), (D)-(IV) (A)-(IV), (B)-(III),(C)-(II), (D)-(I) (A)-(III), (B)-(IV),(C)-(I), (D)-(II) (A)-(IV), (B)-(I),(C)-(II), (D)-(III) |
(A)-(IV), (B)-(III),(C)-(II), (D)-(I) |
The correct answer is Option (2) → (A)-(IV), (B)-(III),(C)-(II), (D)-(I) (A) $y=\log e^x=x\log e=x$ $→y'=1$ and $y''=0$ (B) $y=e^{2x}$ $⇒\frac{dy}{dx}=2e^{2x}⇒\frac{d^2y}{dx^2}=4e^{2x}$ (C) $y=\sqrt{x}$ $⇒\frac{dy}{dx}=\frac{1}{2\sqrt{x}}⇒\frac{d^2y}{dx^2}=\frac{-1}{4x\sqrt{x}}$ (D) $y=e^{-x}$ $⇒\frac{dy}{dx}=-e^{-x}⇒\frac{d^2y}{dx^2}=e^{-x}=\frac{1}{e^x}$ |