Target Exam

CUET

Subject

-- Mathematics - Section A

Chapter

Applications of Derivatives

Question:

Match List-I with List-II

The function $f(x) = 2x^3 - 15x^2 +36x +5$ for $x ∈ [2,5]$ has

List-I

List-II

(A) absolute maximum value

(I) 5

(B) absolute minimum value

(II) 60

(C) point of absolute maxima

(III) 3

(D) point of absolute minima

(IV) 32

Choose the correct answer from the options given below:

Options:

(A)-(I), (B)-(II), (C)-(III), (D)-(IV)

(A)-(II), (B)-(I), (C)-(IV), (D)-(III)

(A)-(II), (B)-(IV), (C)-(I), (D)-(III)

(A)-(II), (B)-(III), (C)-(IV), (D)-(I)

Correct Answer:

(A)-(II), (B)-(IV), (C)-(I), (D)-(III)

Explanation:

The correct answer is Option (3) → (A)-(II), (B)-(IV), (C)-(I), (D)-(III)

List-I

List-II

(A) absolute maximum value

(II) 60

(B) absolute minimum value

(IV) 32

(C) point of absolute maxima

(I) 5

(D) point of absolute minima

(III) 3

$f(x)=2x^3-15x^2+36x+5$ on $[2,5]$

$f'(x)=6x^2-30x+36=6(x^2-5x+6)=6(x-2)(x-3)$

Critical points: $x=2,\;x=3$ (both in the interval)

Evaluate:

$f(2)=2(8)-15(4)+36(2)+5=16-60+72+5=33$

$f(3)=2(27)-15(9)+36(3)+5=54-135+108+5=32$

$f(5)=2(125)-15(25)+36(5)+5=250-375+180+5=60$

Correct matching: A–II, B–IV, C–I, D–III.