If $y=2 x(x-1)(2-x)$; then $\frac{d^2 y}{dx^2}$ is :

$6-12 x$ $12(1+x)$ $12(1-x)$ $6+2 x$

$12(1-x)$

$y=2 x(x-1)(2-x)$ $y=2 x\left(2 x-x^2-2+x\right)$ $y=2 x\left(-x^2+3 x-2\right)$ $y=-2 x^3+6 x^2-4 x$ so differentiating y w.r.t x $\frac{d y}{d x}=-6 x^2+12 x-4$ differentiating again wrt (x) $\frac{d^2 y}{d x^2}=-12 x+12$ $=+12(1-x)$