Proton, deutron and a particles are accelerated through the same potential difference. Then the ratio of their de-Broglie wavelength as :
Answer & explanation
Correct answer: option 2
\(\lambda\) = \(\frac{12.27}{\sqrt{V}}\) A°
Proton, deutron and a particles are accelerated through the same potential difference. Then the ratio of their de-Broglie wavelength as :
Correct answer: option 2
\(\lambda\) = \(\frac{12.27}{\sqrt{V}}\) A°