Match List-I with List-II. Four defective pens are mixed with 10 normal pens. Three pens are drawn one-by-one with replacement. Then the probability distribution of the number of defective pens is :
| List -I | List-II | ||
| (A) | P(X=0) | (I) | $\frac{8}{343}$ |
| (B) | P(X=1) | (II) | $\frac{60}{343}$ |
| (C) | P(X=2) | (III) | $\frac{125}{343}$ |
| (D) | P(X=3) | (IV) | $\frac{150}{343}$ |
Choose the correct answer from the options given below :
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → (A)-(III), (B)-(IV), (C)-(II),(D)-(I)
| List -I | List-II | ||
| (A) | P(X=0) | (III) | $\frac{125}{343}$ |
| (B) | P(X=1) | (IV) | $\frac{150}{343}$ |
| (C) | P(X=2) | (II) | $\frac{60}{343}$ |
| (D) | P(X=3) | (I) | $\frac{8}{343}$ |