Practicing Success

Target Exam

CUET

Subject

Chemistry

Chapter

Physical: Solutions

Question:

Match the entries of column I with appropriate entries of column II and choose the correct option out of the four options given.

Column I Column II
For a 5% solution of H2SO4 (d = 1.01 g mL-1)  
(A) Molarity of the solution (p) 0.537
(B) Molality of the solution (q) 0.0096
(C) Mole fraction of H2SO4 (r) 0.05
(D) Mass fraction of H2SO4 (s) 0.515
Options:

A-r, B-s, C-p, D-q

A-q, B-p, C-s, D-r

A-s, B-p, C-q, D-r

A-s, B-r, C-p, D-q

Correct Answer:

A-s, B-p, C-q, D-r

Explanation:

5% H2SO4 solution means 5 g H2SO4 in 100 g of solution, i.e., solvent (H2O) = 95 g = 0.095 kg

As d = 1.01 g mL-1, volume of 100 g solution = \(\frac{100}{1.01}\) = 99 mL = 0.099 L

$Molarity = \frac{\frac{5}{98}}{0.099} = 0.515 M$

$Molality = \frac{\frac{5}{98}}{0.095} = 0.537 m$

$Mole fraction = \frac{\frac{5}{98}}{\frac{5}{98} + \frac{95}{18}} = \frac{0.051}{0.051+5.278} = 0.0096$

$Mass fraction = \frac{5}{100} = 0.05$