Match the entries of column I with appropriate entries of column II and choose the correct option out of the four options given.
| Column I | Column II |
| For a 5% solution of H2SO4 (d = 1.01 g mL-1) | |
| (A) Molarity of the solution | (p) 0.537 |
| (B) Molality of the solution | (q) 0.0096 |
| (C) Mole fraction of H2SO4 | (r) 0.05 |
| (D) Mass fraction of H2SO4 | (s) 0.515 |
Answer & explanation
Correct answer: option 3
5% H2SO4 solution means 5 g H2SO4 in 100 g of solution, i.e., solvent (H2O) = 95 g = 0.095 kg
As d = 1.01 g mL-1, volume of 100 g solution = \(\frac{100}{1.01}\) = 99 mL = 0.099 L
$Molarity = \frac{\frac{5}{98}}{0.099} = 0.515 M$
$Molality = \frac{\frac{5}{98}}{0.095} = 0.537 m$
$Mole fraction = \frac{\frac{5}{98}}{\frac{5}{98} + \frac{95}{18}} = \frac{0.051}{0.051+5.278} = 0.0096$
$Mass fraction = \frac{5}{100} = 0.05$