Three coins are tossed once. Probability of getting no head is:
Answer & explanation
Correct answer: option 1
Total cases if 3 coins are tossed once = \( {2}^{3} \) = 8
Chance of getting no head is only 1 that is [T,T,T]
Therefore required Probability = $\frac{1}{8}$
The correct answer is Option (1) → $\frac{1}{8}$