CUET Preparation Today
Three coins are tossed once. Probability of getting no head is: |
$\frac{1}{8}$ $\frac{1}{4}$ $\frac{3}{8}$ $\frac{1}{2}$ |
$\frac{1}{8}$ |
Total cases if 3 coins are tossed once = \( {2}^{3} \) = 8 Chance of getting no head is only 1 that is [T,T,T] Therefore required Probability = $\frac{1}{8}$ The correct answer is Option (1) → $\frac{1}{8}$ |
