If $ A +\frac{1}{A} = -1$, then find the value of $\frac{A^6+A^3-1}{A^9+A^3-1}$

0 2 -1 1

1

If $ A +\frac{1}{A} = -1$ Find the value of $\frac{A^6+A^3-1}{A^9+A^3-1}$ If $ A +\frac{1}{A} = -1$ Then, A3 = 1 always Now put the value of A3 in $\frac{A^6+A^3-1}{A^9+A^3-1}$ = $\frac{1^2+1-1}{1^3+1^3-1}$ = 1