Consider the LPP, optimize $Z=x+5y$ subject to $x+y≥5;2x-5y≥10, x≤2; x ≥ 0, y ≥0,$ then which of the following is correct ?
Answer & explanation
Correct answer: option 4
The correct answer is Option (4) → No solution
$x+y≥5⇒\frac{x}{5}+\frac{y}{5}≥1$
$2x-5y≥10⇒\frac{x}{5}+\frac{y}{-2}≥1$
$x≤2$
$(x≥0,y ≥0)$ → first quadrant
Unbounded region
⇒ No. feasible solution exists