Find the mole fraction of the solute if the vapour pressure of a dilute aqueous solution of glucose is 720 mm of Hg at 373 K.

1/11 1/1.1 1/19 115/79

1/19

\(\frac{P^o - P_s}{P^o}\) = Mole fraction of solute Po = vapour pressure of water at 373 K is 760 mm \(\frac{760 - 720}{760}\) = Mole fraction of solute Mole fraction of solute = \(\frac{40}{760}\) = \(\frac{1}{19}\)