If the base radius of a cone is doubled and its height is halved, then volume of the new cone will be:
Answer & explanation
Correct answer: option 3
Let the radius = 1 and height = 1
Now the volume = \(\frac{1}{3}\)πr2h
Old volume = \(\frac{1}{3}\)
New volume when radius of a cone is doubled and its height is halved. = \(\frac{1}{3}\)π(2)2\(\frac{1}{2}\)
= \(\frac{2}{3}\)
we can see that volume is double than earlier.