If the base radius of a cone is doubled and its height is halved, then volume of the new cone will be:

2 times of the original cone

Let the radius = 1 and height = 1

Now the volume = \(\frac{1}{3}\)πr²h

Old volume = \(\frac{1}{3}\)

New volume when radius of a cone is doubled and its height is halved. = \(\frac{1}{3}\)π(2)²\(\frac{1}{2}\)

= \(\frac{2}{3}\)

we can see that volume is double than earlier.