12 men or 20 boys can finish a work in 10 days. What part of the same work will be done by 4 men and 4 boys in 4 days?
Answer & explanation
Correct answer: option 2
Formula to be used here;
\( { M}_{1 } \) x \( { D}_{1 } \) = \( { M}_{2 } \) x \( { D}_{2 } \),
⇒ 12M x 10 = 20B x 10
⇒ M : B
Efficiency 5 : 3
⇒ Total Work = 12 (5) x 10 = 600 units.
⇒ Work done by 4 men and 4 boys in 4 days = \(\frac{W}{32}\) = 4
⇒ W' = 128 units
⇒ W' is % of total work = \(\frac{128}{600}\) = \(\frac{16}{75}\).