Out of the following $1.0\text{ M}$ aqueous solutions, which one will show the largest freezing point depression? |
$\text{NaCl}$ $\text{Na}_2\text{SO}_4$ $\text{C}_6\text{H}_{12}\text{O}_6$ $\text{Al}_2(\text{SO}_4)_3$ |
$\text{Al}_2(\text{SO}_4)_3$ |
The correct answer is Option (4) → $\text{Al}_2(\text{SO}_4)_3$ ## Because it generatees higher number of ions after dissociation. $\text{Al}_2(\text{SO}_4)_3 \rightarrow 2\text{Al}^{3+} + 3\text{SO}_4^{2-}$ $2 + 3 = 5$ |