A network of resistors is connected to a 16 V battery as shown in figure. Compute the equivalent resistance of the network.
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → \( 7\,\Omega \)
The network is three groups in series: the two \( 4\,\Omega \) resistors in parallel between A and B, the \( 1\,\Omega \) resistor between B and C, and the \( 12\,\Omega \) and \( 6\,\Omega \) resistors in parallel between C and D. Find each group and then add them.
A to B (\( 4\,\Omega \) and \( 4\,\Omega \) in parallel)
\( \displaystyle R_{AB} = \frac{4\times4}{4+4} = 2\,\Omega \)
C to D (\( 12\,\Omega \) and \( 6\,\Omega \) in parallel)
\( \displaystyle R_{CD} = \frac{12\times6}{12+6} = 4\,\Omega \)
Total
\( R_{\mathrm{eq}} = R_{AB} + R_{BC} + R_{CD} = 2 + 1 + 4 = 7\,\Omega \)