A network of resistors is connected to a 16 V battery as shown in figure. Compute the equivalent resistance of the network.
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → $7 \Omega$
$\frac{1}{R_{AB}}=\frac{1}{4}+\frac{1}{4}⇒R_{AB}=2Ω$
$\frac{1}{R_{CD}}=\frac{1}{12}+\frac{1}{6}⇒R_{CD}=4Ω$
$∴R_{eq}=4+2+1=7Ω$