CUET Preparation Today
A network of resistors is connected to a 16 V battery as shown in figure. Compute the equivalent resistance of the network.
|
$5 \Omega$ $7 \Omega$ $9 \Omega$ $11 \Omega$ |
$7 \Omega$ |
The correct answer is Option (2) → $7 \Omega$
$\frac{1}{R_{AB}}=\frac{1}{4}+\frac{1}{4}⇒R_{AB}=2Ω$ $\frac{1}{R_{CD}}=\frac{1}{12}+\frac{1}{6}⇒R_{CD}=4Ω$ $∴R_{eq}=4+2+1=7Ω$ |
