For a cell reaction involving two electron change, the standard EMF of the cell is 0.295 V at 25∘C. What is the equilibrium constant of the reaction at 25∘C?
Answer & explanation
Correct answer: option 2
The correct answer is option 2. \(1 \times 10^{10}\)
\(E^o_{cell} =\) \(\frac{2.303RT}{nF}\)logKc = \(\frac{0.0591}{n}\) logKc
∴ 0.295 V = \(\frac{0.0591}{2}\) logKc
or logKc= \(\frac{0.295 × 2}{0.0591}\) =10
or Kc=1×1010