For a cell reaction involving two electron change, the standard EMF of the cell is 0.295 V at 25^∘C. What is the equilibrium constant of the reaction at 25^∘C?

1 x 10¹⁰

The correct answer is option 2. \(1 \times 10^{10}\)

\(E^o_{cell} =\) \(\frac{2.303RT}{nF}\)logKc = \(\frac{0.0591}{n}\) logK_c​

∴ 0.295 V = \(\frac{0.0591}{2}\) logK_c​

or logK_c​= \(\frac{0.295 × 2}{0.0591}\) =10

or K_c​=1×10¹⁰