Practicing Success
If the areas of two isosceles triangles are in the ratio of $x^2: y^2$, then the ratio of their corresponding heights is: |
x : y $\sqrt{x}:\sqrt{y}$ $x^3:y^3$ $x^2: y^2$ |
x : y |
Concept Used Area of 1st triangle : Area of 2nd triangle = \( {Height\; of\; 1st\; triangle }^{2 } \) : \( {Height\; of\; 2nd\; triangle }^{2 } \) Calculation ⇒ \( {x}^{2 } \) : \( {y }^{2 } \) = \( {Height\; of\; 1st\; triangle }^{2 } \) : \( {Height\; of\; 2nd\; triangle }^{2 } \) ⇒ x : y = Height of 1st triangle : Height of 2nd triangle Therefore, the answer is x : y |