In an alloy 80% copper and rest is tin. In another alloy copper 85% and 13% tin. Both are mixed in which ratio such that percentage of tin becomes 15% in resultant mixture.
Answer & explanation
Correct answer: option 3
In first alloy tin percentage = 100 - 80 = 20%
In second alloy tin percentage = 13%
After mixing tin percentage = 15%
Now using allegation method with tin percentage:
Therefore, alloy be mixed in the ratio = 2 : 5