In the nuclear reaction given below, a neutron hits a uranium nucleus. The values of $a$ and $b$ are respectively
$n + {^{235}_{92}U}→{^{a}_{54}Xe} + {^{94}_{b}Sr} + 2 n$
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → 140 and 38
Reaction:
$ \; ^1_0n + ^{235}_{92}U \;\;\to\;\; ^a_{54}Xe + ^{94}_bSr + 2 \; ^1_0n $
Conservation of mass number (A):
$1 + 235 = a + 94 + 2(1)$
$236 = a + 96$
$a = 140$
Conservation of atomic number (Z):
$0 + 92 = 54 + b + 0$
$92 = 54 + b$
$b = 38$
Answer: $a = 140, \; b = 38$