In $\triangle \mathrm{ABC}, \angle \mathrm{A}=50^{\circ}$. If the bisectors of the angle $B$ and angle $C$, meet at a point $O$, then $\angle B O C$ is equal to:
Answer & explanation
Correct answer: option 4
= \(\angle\)BOC = 90 + \(\frac{A}{2}\)
= 90 + 25 = \({115}^\circ\).