In the expression of Gauss's Law. $\int\vec E.\vec{ds}=q/ε_0$ (B) The electric field on LHS is only due to the charges inside the Gaussian surface. Choose the correct answer from the options given below: |
(A) only (B) only (C) only (D) only |
(B) only |
The correct answer is Option (2) → (B) only The flux depends on the total field at the surface (due to both inside and outside charges), but Gauss's Law relates it only to the charges enclosed inside. |