$\int\frac{\sqrt{\tan x}}{\sin x\cos x}dx$ is equal to:
Answer & explanation
Correct answer: option 1
$I=\int\frac{\sqrt{\tan x}}{\sin x\cos x}dx=\int\frac{\sqrt{\tan x}}{\tan x}\sec^2x/,dx=\int\frac{1}{\sqrt{t}}dt$, where t = tan x
$I=2t^{1/2}+C=2\sqrt{\tan x}+C$