$\int\frac{\sqrt{\tan x}}{\sin x\cos x}dx$ is equal to:

$2\sqrt{\tan x}+C$ $2\sqrt{\cot x}+C$ $\frac{\sqrt{\tan x}}{2}+C$ None of these

$2\sqrt{\tan x}+C$

$I=\int\frac{\sqrt{\tan x}}{\sin x\cos x}dx=\int\frac{\sqrt{\tan x}}{\tan x}\sec^2x/,dx=\int\frac{1}{\sqrt{t}}dt$, where t = tan x $I=2t^{1/2}+C=2\sqrt{\tan x}+C$