If $P(A) = \frac{4}{5}$ and $P(A \cap B) = \frac{7}{10}$, then $P(B \mid A)$ is equal to
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → $\frac{7}{8}$ ##
Since, $P(A) = \frac{4}{5}, P(A \cap B) = \frac{7}{10}$
$∴P(B \mid A) = \frac{P(A \cap B)}{P(A)} = \frac{7/10}{4/5} = \frac{7}{8}$