If $P(A) = \frac{4}{5}$ and $P(A \cap B)

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Target Exam

CUET

Subject

Maths. Section B1

Chapter

Probability

Question:

If $P(A) = \frac{4}{5}$ and $P(A \cap B) = \frac{7}{10}$, then $P(B \mid A)$ is equal to

Options:

$\frac{1}{10}$

$\frac{1}{8}$

$\frac{7}{8}$

$\frac{17}{20}$

Correct Answer:

$\frac{7}{8}$

Explanation:

The correct answer is Option (3) → $\frac{7}{8}$ ##

Since, $P(A) = \frac{4}{5}, P(A \cap B) = \frac{7}{10}$

$∴P(B \mid A) = \frac{P(A \cap B)}{P(A)} = \frac{7/10}{4/5} = \frac{7}{8}$