A teacher distributes some sweets among his four students in the ratio of $\frac{1}{3} : \frac{1}{5} : \frac{1}{6} : \frac{1}{4}$. What is the minimum number of sweets that the teacher should have, so that no sweet needs to be broken into parts to be shared?

57

A teacher distributes sweets to four students in the ratio

\(\frac{1}{3}\) : \(\frac{1}{5}\) : \(\frac{1}{6}\) : \(\frac{1}{4}\)

⇒ Taking LCM 60, ratios become,

⇒ 20 : 12 : 10 : 15,

⇒ What is the minimum number of sweets that the teacher should have, so that no sweet needs to be broken into parts to be shared = 20 + 12 + 10 + 15 = 57.