Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section B1

Chapter

Applications of Derivatives

Question:

The straight line $\frac{x+2}{3}=\frac{z-3}{-2}, y=2$ is

Options:

parallel to x-axis

parallel to y-axis

parallel to z-axis

perpendicular to y-axis

Correct Answer:

perpendicular to y-axis

Explanation:

The correct answer is Option (4) → perpendicular to y-axis

Line in standard form

$\frac{x+2}{3}=\frac{z-3}{-2}=\frac{y-2}{0}$

DC: 3, 0, -2

DC (y-axis) : 0, 1, 0

cross product of DCS = 0 ⇒ line ⊥ y-axis