In YDSE, the intensity of the central ma

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Target Exam

CUET

Subject

Physics

Chapter

Wave Optics

Question:

In YDSE, the intensity of the central maximum is I. What will be the intensity at the same point when one slit is closed ?

Options:

I/2

I/4

Correct Answer:

I/4

Explanation:

Intensity $I = (\sqrt I_1 + \sqrt I_2)^2 = (\sqrt I_1 + \sqrt I_1)^2 = 4I_1$

When one slit is closed , the intensity will be $I_1 = \frac{I}{4}$