The range of the function $f(x)=\frac{1}{3-\sin 4x}$ is :
Answer & explanation
Correct answer: option 1
$f(x)=\frac{1}{3-\sin 4x}$
$-1≤\sin 4x≤1$
$-1≤-\sin 4x≤1$
$2≤3-\sin 4x≤4$
$\frac{1}{4}≤\frac{1}{3-\sin 4x}≤\frac{1}{2}$
The range of the function $f(x)=\frac{1}{3-\sin 4x}$ is :
Correct answer: option 1
$f(x)=\frac{1}{3-\sin 4x}$
$-1≤\sin 4x≤1$
$-1≤-\sin 4x≤1$
$2≤3-\sin 4x≤4$
$\frac{1}{4}≤\frac{1}{3-\sin 4x}≤\frac{1}{2}$